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Assume a plane stress load case for the double lap (double plate) joint for three plates. Plate is sandwiched by Plate 2 and Plate 3. They are joined by a fastener. Assume that Plate 2 and Plate 1 are subjected to axial loads of 10,000 lbs and 12,000 lbs respectively. Furthermore there is an external axial load T of 1000 lbs acting on the fastener The bar has a length of 15 inches, a height of 4 inches and a depth of 2 in. The centerline to centerline distance Di between Plate 2 and Plate 1 is 1.5 in. The centerline to centerline distance D2 between Plate 3 and Plate 1 is 2 in. T 1000 lbs Fastener Head Plate 2 height Centerline -P 10000 lbs Di Centerline length P 12000 lbs Plate 3 Compute the stresses at the left-hand side boundary for the top, middle and bottom of the plate. You may assume that Plate 2, Plate 3 and the fastener can be modeled as rigid bodies and that the fastener hole in Plate 1 will not elongate. a) b) Assume that the material is Aluminum 7178, compute the SF using both Von Mises and Tresca criterion at the neutral axis as well as the top and bottom face of the beam at the left-hand boundary. The yield strength of Aluminum 7178 is 71.067 kpsi. c) Assume that the material is grade 30 cast iron, utilize the Coulomb - Mohr failure model to calculate the safety factor. The ultimate tensile strength is 31 kpsi and the ultimate compressive strength is 109 kpsi. Comment on when it is acceptable to use the Von Mises vs. Coulomb-Mohr failure criterion. From part a, the chief engineer would like you to double the safety factor for the worst case stress. While your material selection is fixed, you have been given the freedom to modify the height and width of Plate 1. Present two design solutions and comment on their efficiency. For simplicity, you can assume that the centerline to centerline distances do not change. d)

Answer 1

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