Question

PYTHON! If From = 1235, To = 7124, take Sum_A = SumOfSqrOfInts_A(From,To) Sum_B = SumOfSqrOfInts_B(From,To) Find Sum_A/ Sum_B, then print out the answer out to five decimal places. Find the cube root of the cube of Sum_A, then print the result out without rounding. Explain the result. Copy the output from the shell, put it below your code and comment it out. Output should be of the following form. The underscore are the appropriate numbers.

Q3:

Sum_A is ___________

Sum_B is ___________

The ratio of Sum_A to Sum_B for From,To = 1235,7124, to five decimals, is _________

The cube root of the cube of Sum_A is ________________

Answer 1

PYTHON CODE :

BECAUSE OF IDENTATION PROBLEM IAM SUMITTING CODE THROUGH SCREENSHOT :

def SumOfSqrofInts_A(From, To) : SA = 0 for i in range(From, To+1) : SA += i*i # sum of squares return SA # return Sum A def SumofSqrofInts_B(From, To) :| SB = 0 for i in range(From, To+1) : SB += i*i # sum of squares return sВ # return Sum_B From = 1235 # initialize From varaible To = 7124 # initialize To varaible Sum_A = SumofSqrofInts_A(From, To) # call functions SumofSqrofInts_A Sum_B = SumofSqrofInts_B(From, To) # call fucntion SumofSqrofInts_B print("Sum_A is", Sum_A) # print Sum_A print("Sum_B is", Sum_B) # print Sum_B print("The ratio of Sum_A to Sum_B for From, To = 1235,7124, to five decimals, is", round(Sum_A/Sum_B, 5)) print("The cube root of the cube of Sum_A is", (Sum_A * Sum_A) ** 1/3) # cube root of cube of Sum_A Sum_A

OUTPUT :

Sum_A is 119915855865 # prints sum of A

Sum_B is 119915855865 # prints sum of B

The ratio of Sum_A to Sum_B for From,To = 1235,7124, to five decimals, is 1.00000 # ratio of sum_A and sum_B

The cube root of the cube of Sum_A is 5.7478917388566785e + 32 # cuberoot of cube of sum_A