Question

per phase. The line feeds a balanced delta-connected load, which absorbs a total complex power of 12 + 15 kVA. The line voltage at the load end has A three-phase line has an impedance of 1 + 3 a magnitude of 220 V. References eBook & Resources Section Break Difficulty: Medium Learning Objective: Understanding and analyzing power in balanced three-phase circuits. value: 10.00 points Required information Find the source power factor. The source power factor pf = 327.88.

Answer 1

The source power factor is 0.7075, and it is calculated as given below:

Soluhon- • According to ginen em ditions :- vioad (line) = 220V load impedomee (ZL) = ? land power consumed 51 = (12495)kVA line impedance Kline) = (1+j3)2 1. The, circuit diagram of abone giren system is shown & chat 22OV assun su Soun na UU AmoyB to utis) C + j3) 2 stebt: Here, Vline Clowed) = 220V en Vab = 220V (assumed, refessence). Here, phase loced collage, Van Clocicl) = 900 x Van Clod) = (127.017) V-0 C Now, assume this as reference) Step-2: Now, solving easily assumed source is star connecte Step-3: Now, per phase power consumed by load: Shop = (P1-P7301-03 51-4 = (12+ j5) = (4+)167) KvA step-u: Now, line cw.sent for food :- Iline= $ = 5(4+j1-67 )xlovo ? 1270017 Ilinet = 34.116 2 2262° Trine = 34•1162 2-22-62" | Skep-5! Now, we can calculate source voltage as: - Vsource (phase) = Vload (phase) + Iline Zline = 3(127.01720) + (3461162 L-22-62)Cl+j3) TVsouscephant 213-95222.35° rolls - Step-6. Now, source power factor is calculated as :- Iline - Vload (phose) source powers fecetor = cos( ongle ble souvie vlg and current) = cos ( 22:35 – (-2262)) = CO ( 44.970) los of source 0.7075 | Any & Required source power factor