Draw the structure of the compound C9H10O2 that exhibits the 13C-NMR spectrum below. Impurity peaks are omitted from the peak list. The triplet at 77 ppm is CDCl.
Shift
190.6; 164.0; 131.9; 129.8; 114.7; 63.9; 14.6
First we have to calculate number of index hydrogen deficiency by comparing with saturated hydrocarbon formula ,
CnH(2n+2)
here n= 9 , number of carbon atoms , C9H10O2 by comparing ,
C9H (2 x 9 + 2)
C9H 20
index hydrogen deficiency = (20-10)/2,
here 10 stands for number of hydrogen in molecular formula so index hydrogen deficiency = 5
now it is clear that compound contain aromatic ring and one characterstic peak at 190.6 ppm indicates presence of carbonyl group. So based on chemical shift of CMR , compound would be 4-Methoxyacetophenone,
A=190.6 ppm
B=164.0 ppn
C=131.9 ppm
D= 129.8 ppm
E=114.7 ppm
F=63.9 ppm
G= 14.6 ppm
Draw the structure of the compound C9H10O2 that exhibits the 13C-NMR spectrum below. Impurity peaks are...
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