Question

a 5.0 kg mass has a spring, k = 80 N/m, attached to it and it is moving at 6.0 m/s to the right. the end with the spring collides with a 10 kg mass that is stationary. determine the maximum compression of the spring

Answer 1

1. m, = 5 kg ma= lokg. 1 . K = 80 N/m u,= 6.0 mys U₂=0 using conseruation of linear momentum . momentum before collision = after collision 1 minit malų =(Mitha) v . 5x6 +0 = 5+10) V - 15v= 30 v=2 m/s Now using conservation of energy: - KIE. of m, before collision =k. E. of combined mass.after collision + Elastic P.E. of spring å mini" = a (m, + m2 75+ å ku² > fx566)* = $(5+10)()* +* *808? 180 = 60 + 80% 80x = 180-60=120 x²= 12 2 = 1.5 m² .: n=1.5m a = 1.22 m)