Question

Question 3 A caliper brake is required for the front wheels of a passenger car with a braking capacity of 500 Nm for each brake. Preliminary design estimates have set the brake geometry as n = 110 mm' and 8 = 43º. Pads with a coefficient of friction of 0.38 have been selected. Each pad is actuated by means of a hydraulic cylinder of nominal diameter 25.4 mm. Determine: 3.1 3.2 3.3 the required actuating force, the average and the maximum contact pressures, the required hydraulic pressure for brake actuation. [10] The student is to take the outer radius of the brake to be that of the Bugatti Chiron.

Answer 1

given Torque Capacity (I) = 500 Nm H=0.38 ri = 110 mm ☺ To = 200 mm (for Bugatti Chiron) 0 = 439 Nominal Diamald) = 25.4 mm Porque per pad = T = Soo e 250 Nm. . effective radius (Xe) = 110+200 - 155mm Actuation force (f) = TM F = 250 Nm - = 4.944.482 N. (0.38)*(0.155) 2 S ure © Maximum Pressuse! F 4244.482 Pmax - Drilo-7) 43x12xolo 439(202) * 0.11(0.2-0.11) = 4.7606x105. NMP Average Pressure! Pauge 21 ) x Prom Pmax = 2 1012). _x 4.7606x105. 02 -X 4.7 60 6X10° = 3.3784X105

© Area of hydraulic Cylindes!. . A = 7x82 = ax (0.0127) 2 = 5.067 x104m2 Required hydraulic Pressuse!. Prud e f = 4844.482 N. 5.0678 104 m2 = 8.3767 X10% Ne Phyd = 8.3767x10€

Hope this is helpful. Feel free to ask any doubt.