Question

R R3 w RS ww Vsi R₂² RA Vsa ia ib ic Q2. In the circuit, Vs1 - 37 V, Vs2 - 19 V, R1 - 2 Ohm, R2 - 7.5 Ohm, R35 Ohm, R4 - 5.5 Ohm, R5 - 3 Ohm. A. Select the correct answer for the following question Each equation of the mesh analysis technique states that Correct: The sum of all voltages around the closed loop is zero. Incorrect The sum of voltages across all the elements connected to the node is zero. Incorrect The currents flowing trhough each element of the mesh are equal Incorrect The sum of all the currents flowing in and out of the node is zero. You are correct. Previous Tres Your receipt no is 155-23422 B. Assume that the mesh currents are defined as la, ib and ic as shown in the circuit diagram Using the notations of the caption below circuit diagram (case sensitivel), write the mesh equations for the circuit keeping all the terms on the left hand side (US), so (1.1) Enter the left-hand side of mesh equation for the mesh "a" Vs1-laR1-ia-ib)"R2 - 0 You are correct, Your receipt no. is 155-877 Previous Tries (8.2) Enter the left hand side of mesh equation for the mesh "b" -(ib-ia) R2-ib*R3-(ib-ic)R4 - 0; You are correct. Your receipt no is 155-5880 Previous Ties (8.3) Enter the left hand side of mesh equation for the mesh "C"
im not sure what to do wjrh the rest

Answer 1

RE Me Rz Rs WWE 1 Usz Vsi Ry B.3: The Left hand side of mesh equation ty mesh e is. the mesh equation of lb then the mesh equation for it R₂ (bla) + Rzebt Rylez lc) = 0 Erzya + (RHR3+Ry) és+(-Rubic=0 -Rolat (Ryt Rgtly) is-Ry ic=0 Ansi - Relat (R2 + Ryt Ry) ix-Ryle "Mesh equations : -Vsi +R lat R₂ (da 16 = 0 talRot Ry) hib = vso - As shown in above B.3. - Rzia +(Rat Rytry) is-Pulczo-③ +Vs+Rulle is) + Rpic=0 -Rylb + (Ryths) ic - Vsz

C.1: By substituttg Given cincuit components in Meh equations O-> 9.54a-7.515=37 -7.56at 1816-5.5 (c=0 (3 -5.5 16+8.50.= - 19 By solving these arequations we get by a=5.46 , db=1.98 le=-0.95 o la = 5.46 amps C. 2: (16=1.98 ] amps C.3: Tic= -0.95 Jamps. chi Abo dute value of volkage across R2 = (da-ib) R2 = (5.46-1098)*7.5 = 3.48x7.5 - 26.1 volts. // C5 Absolute Values of voltage across R3 - 1.9845 -9.9 volts. //