Question

How many moles of ammonia can be made by reacting 5.70 moles of N₂ with 4.95 moles of H₂?

N₂ (g) + 3 H₂ (g) --> 2 NH₃ (g

Answer 1

From the balanced equation:

N2 (g) + 3 H2 (g) ----------> 2 NH3 (g)

From this reaction, one mole of N2 react with three moles of H2. So, for the reaction of 5.7 moles of N2, number of mole require for H2 = 3 x 5.7 = 17.1 moles.

But here you have only 4.95 moles of H2 (reqired 17.1 moles)

Hence, the limiting reagent is H2 here.

Now, 3 mole of H2 provide 2 mole of NH3

So, after reaction of 4.95 moles of H2, produced NH3 = (2 x 4.95) / 3

= 9.9 / 3

= 3.3 moles of NH3