1. An experiment occurs where 800 J of thermal energy are absorbed by a sample of...
1. An experiment occurs where 800 J of thermal energy are absorbed by a sample of water in a highly insulated environment. In a second experiment 800 J are absorbed by another sample of water that has three times the mass as the first, in a similar environment. In each case a temperature reading is made before the energy is absorbed and then again after the energy is absorbed and distributed throughout the sample (equilibrium reached).
a. Will the change in the temperature (before and after) of the water be the same for the two experiments? Why or why not?
b. How can any differences in temperature change be explained using an atomic model of the water samples?
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1. An experiment occurs where 800 J of thermal energy are
absorbed by a sample of...
Thermal Efficiency Internal Heat Energy AQ (J) Energy Lost (1) Material Work (J) Thermal Efficiency (%)...
Thermal Efficiency Internal Heat Energy AQ (J) Energy Lost (1) Material Work (J) Thermal Efficiency (%) Aluminum 89.89 63.55 26.34 70.70 Brass 49.09 39.74 9.35 80.95 3.) Show your work. Aluminum Energy Lost-89.89-63.55=26.34 J Aluminum Thermal Efficiency (%). e=q/w = 63.55/89.89x100=70.70% Friction Heating - 5 Brass Energy Lost- 49.09-39.74=9.35J Brass Thermal Efficiency..(%)-e=q/w = 39.74/49.09 x100=80.95% Results and Questions 1.) Give the equation you used to calculate the Power required to lift the mass. 2.) How did the internal energy change...
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The first law of thermodynamics In thermal physics, we are often interested in the internal energy...
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just the last one
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Section I: First Order Systems 1) A microwave oven is used to heat a cylindrical glass...
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Thermal Efficiency Internal Heat Energy AQ (J) Energy Lost (1) Material Work (J) Thermal Efficiency (%) Aluminum 89.89 63.55 26.34 70.70 Brass 49.09 39.74 9.35 80.95 3.) Show your work. Aluminum Energy Lost-89.89-63.55=26.34 J Aluminum Thermal Efficiency (%). e=q/w = 63.55/89.89x100=70.70% Friction Heating - 5 Brass Energy Lost- 49.09-39.74=9.35J Brass Thermal Efficiency..(%)-e=q/w = 39.74/49.09 x100=80.95% Results and Questions 1.) Give the equation you used to calculate the Power required to lift the mass. 2.) How did the internal energy change...
The first law of thermodynamics In thermal physics, we are often interested in the internal energy (E) of a system. The wo 41 internal energy of an ideal gas is proportional to the temperature and the number of moles of the gas. The internal energy can change when energy is exchanged with the system's environment (ie., objects that are outside the system of interest). The case above is one in which the internal energy of a gas changes due to...
1. Calculate the change in internal energy ΔΕ when 15.6 kJ of heat is added to the system and 1.4 kJ of work is done to the system. 2. How much work can a bicycle pump perform when the the cylinder compresses from 3L to 2.5 L as you apply a pressure of 1.1 atm? J. A hot air baloon expands from 4,00,000L to 4.00,000L by the addion of 130,000000 of eat energy Calculate the change in energy of the...
just the last one
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Section I: First Order Systems 1) A microwave oven is used to heat a cylindrical glass beaker completely full of water. The magnetron tube generates 800 watts of thermal power, all of which is absorbed by the water. The glass beaker sits on a thermally insulated plate. As the microwaves increase the temperature of the water, the beaker temperature will also increase due to conduction and convection from the Mode Stirrer Wave Guide Magnetron Tube (source of radiation) Oven Cavity...
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Calorimetry Materials: Styrofoam cup & lid Digital thermometer Metal sample Graduated cylinder Beaker Test tube with stopper Heating setup for beaker Behind a calorimetry experiment is the known occurrence of heat flow from a warm object to a cooler object. Heat scales with the amount of matter and also depends on the resistance of an object to change temperature. Temperature is just the average of the amount of energy contained inside a given area. Heat is represented by the letter...
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