Question

just the last one

Energy Content of Foods DATA Sample 2 Popcorn Sample 1 Rip 1 218 Food used Mass of food and holder (initial) Mass of food and holder (final) Mass of empty can Mass of can plus water Initial water temperature Final water temperature 978 1018 63.44 18.5 °C 22.4°C JEN 2,7 °c 36.5 °C PROCESSING THE DATA 1. Calculate change in water temperature, Ar, for each sample, by subtracting the initial temperature from the final temperature (Ar=tfinal-initial) sample Sample2 22,9-18,5 -4,4 36,5 - 21.7=14.0. 2. Calculate the mass (in g) of the water heated for each sample. Subtract the mass of the empty can from the mass of the can plus water. 63,44 - 15 = 48.44 3. Use the results of Steps 1 and 2 to determine the heat energy gained by the water in J). Use the equation H = At-m-Cp where H = heat absorbed in J), At=change in temperature (in °C), m = mass of the water heated in g), and Cp = specific heat capacity (4.18 J/gºC for water). 4 8 .44 24,28

Answer 1

The heat absorbed by the water is calculated:

Sample 1:

H = 4.4 ° C * 4.18 J / g * ° C * 48.44 g = 890.9 J

sample 2:

H = 14.8 ° C * 4.18 J / g * ° C * 48.44 g = 2996.7 J

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