we know, for glass refractive index = 1.5
let theta_i is the angle of incidence
and theta_r is the angle of refraction
given, theta_r = theta_i/2
Apply Snell's law
n1*sin(theta_i) = n2*sin(theta_r)
1*sin(theta_i) = 1.5*sin(theta_r)
2*sin(theta_i/2)*cos(theta_i/2) = 1.5*sin(theta_i/2)
cos(theta_i/2) = 1.5/2
theta_i/2 = cos^-1(0.75)
theta_i/2 = 41.4
theta_i = 41*4*2
= 82.8 degrees <<<<<<<<<---------------Answer
Problem 18.49 Part A What is the angle of incidence in air of a light ray...
3. At what angle of incidence in air would a ray of light have to enter crown glass to have a refraction angle of 26 degrees? 4. The speed of light in medium M is 2.69x10^9 m/s. What is the critical angle in M (relative to air)?
The angle of refraction of a ray of light traveling through an ice cube is 38\({\rm ^\circ}\). Part A Find the angle of incidence. (^\circ\) Express your answer using two significant figures.
Light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. The sheet has parallel faces and the glass has an index of refraction 1.50. (a) What is the angle of refraction in the glass? (6) After traveling through the glass the light re-emerges into the air. What is the final angle of refraction in air? () As it leaves the glass, by what distance is the path of the ray is displaced from...
QUESTION 1 A light ray in air strikes a glass surface with an angle of incidence of 48°. The angle of refraction in the glass is 29º. What is the speed of light in the glass in 108 m/s calculate in 108 and write only the number e.g. 2x 108 write only 2
How does the angle of incidence compare with the angle of refraction when a light ray passes from air into glass at a nonzero angle?
The angle of incidence of a light ray from Air into a glass slab thickness t=2.5 cm is Theta n=60.0 degree The index of refraction of the glass n=1.6 z. obtain the angle of reflection Theta ref and the refracted ray from the back side of the disk as Shown.
Ray Optics 1 Problem Statement Light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. The sheet has parallel faces and the glass has an index of refraction 1.50. (a) What is the angle of refraction in the glass? (b) After traveling through the glass the light re-emerges into the air. What is the final angle of refraction in air? (c) As it leaves the glass, by what distance is the path of...
Ray Optics 1 Problem Statement Light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. The sheet has parallel faces and the glass has an index of refraction 1.50. (a) What is the angle of refraction in the glass? (b) After traveling through the glass the light re-emerges into the air. What is the final angle of refraction in air? (c) As it leaves the glass, by what distance is the path of...
Ray Optics 1 Problem Statement Light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. The sheet has parallel faces and the glass has an index of refraction 1.50. (a) What is the angle of refraction in the glass? (b) After traveling through the glass the light re-emerges into the air. What is the final angle of refraction in air? (c) As it leaves the glass, by what distance is the path of...
Ray Optics 1 Problem Statement Light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. The sheet has parallel faces and the glass has an index of refraction 1.50. (a) What is the angle of refraction in the glass? (b) After traveling through the glass the light re-emerges into the air. What is the final angle of refraction in air? (c) As it leaves the glass, by what distance is the path of...