Question

Please explain how you got the answer. Thank you!

(1 point) A scientist was testing to detemine if the resistance of electrical wire can be reduced by alloy ing the wire She obtained 46 values for standard wiring and found the average to be z = 0.128 ohm and sz-0.11 ohm, and she obtained 46 values for alloyed wire which resulted in = 0.078 ohm and su-0.088 ohm. With this data construct a 90% confidence interval for the true difference between the average resistance of the two kinds of wire,

Answer 1

Answer Date: 27/04/2016 A 90% confidence interval for the true difference between the average resistance of the two kinds of wire is, By using MINITAB, find confidence interval with the help of the following steps 1) Import the data. 2) Select the Stat and choose the Basic Statistics option 3) Select the 2 sample t and enter Summarized data 4) Select Assume equal variances. 5) Click option button choose Confidence level, Test difference and alternative hypothesis. 6) Click Ok. Two-Sample T-Test and Cl Sample NMean StDev SE Mean 2 46 0.128 0.110 0.016 46 0.0780 0.0880 0.013 Difference = mu (1) -mu (2) Estimate for difference: 0.0500 90% CI for difference : (0.0155, 0.0845)

From the MINITAB output, a 90% confidence interval for the true difference between the average resistance of the two kinds of wire is 0.016 to 0.085