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Show how the final concentration of Iodate ion in an experimental run was obtained using the...

Show how the final concentration of Iodate ion in an experimental run was obtained using the values: initial, M = 0.00500M and final, M = 0.00400M. The balanced equation of the reaction is 5 SO​​ ​​​-​2​3 (aq) + 2 IO ​3​- (aq)+ 2 H  ----- ->>>>>   I​2 (aq) +5 SO-​2 ​​4 (aq) +H20 (aq) . Please show ALL your work.

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Answer #1

We can apply equivalent concept

Eq. of I2=Eq of IO3- reacted

Final conc of iodate = initial conc - reacted conc

So conc falls during reaction run

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