Question

FINITE MATH

LONE STAR COLLEGE UNIVERSETY PARK Prof. Ivan Ramos-Medina Final Test Review Math 1324 Finite Math Solve the following exercises of Simple Interest using the formula 1. A - P(1+rt). Maria is planning to buy a used car. Cuajito's Cars is offering her to pay $5,000 for the car, including the annual rate of 10%. Juanita will pay it in 9 months. How much is the principal she needs to pay? Solve the following exercise of Compound Interest using the formula A P(m, Susan invested $2,000 at 79% compounded quarterly. How much is the quantity after 5 years? 2. Solve the following exercise of Continuous Compound Interest using the formula A Pert. How long it will take $42,000 to grow to $60,276 if it is invested at 4.25%? 3. 4. Solve the following equation systems by the substitution system 3x+4y 1 x -2y 7

Please show work , I’ve already have the basic fundamentals on how to do this , so there is no need to write what you are doing, i just need help solving it so I can study . Best regards !

Answer 1

Amount = 5000 Rate = 10/100 = 0.1 Time = 9/12 years = 3/4 years Amount = p(1 + rt) 5000 = p(1 + 1/10 times 3/4) 5000 = p(1 + 3/40) => 5000 = p(43/40) => 5000 times 40/43 = p => p = 4651.16 principal = 4651.16 Amount = ? principal = 2000 interest = 0.07 time = 5 years m = 4 \r\n A = p(1 + r/m)t_m Amount = 2000 (1 + 7/400)^20 A = 2000 (407/400)^20 Taking log both sides log A = log 2000 + 20 [log 407 - log 400] log A = 3.3010 + 20 [2.6095 - 2.6020] = 3.3010 + 20 [0.0075] = 3.451 Taking antilog both sides A = 2825.0 So, Amount = $2825 \r\n principal = 42000 Amount = 60276 Rate = 4.25/100 A = pe^rt 60276 = 42000 e^(0.0425)t 60276/42000 = e^(0.0425)t taking log both sides log 60276 - log 42000 = (0.0425)t 4.7801 - 4.6232 = 0.0425 0.1569/0.0425 = t t = 3.69 years \r\n 3x + 4y = 1 -(1) x - 2y = 7 -(2) x = 7 + 2y -(3) put the value in eqn (1) 3[7 + 2y] + 4y = 1 21 + 6y + 4y = 1 10 y = -20 y =