Which of the following metals could really be used as sacrificial anodes for iron (Fe2+(aq) +...
Which of the following metals could really be used as sacrificial anodes for iron (Fe2+(aq) + 2e??Fe(s), E0 =-0.44V )?
| A) Tin | F) Magnesium |
| B) Zinc | G) Lithium |
| C) Aluminum | H) Copper |
| D) Lead | I) Nickel |
| E) Sodium | J) None of the above |
Enter all that apply in alphabetical order (e.g. AB, ABDF, etc.)
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Which of the following metals could really be used as
sacrificial anodes for iron (Fe2+(aq) +...
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half reactions are:
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this is all the information I was given
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46.) A zinc sacrificial anode would be effective at protecting
all of the following metals, EXCEPT...
47.) Which answer best describes the strongest intermolecular
force that can exist between two long chain polymer molecules of
polyethylene?
When the temperature of a polymer sample is below it's glass
transition temperature (Tg)
Question 46 3 pts A zinc sacrificial anode would be effective at protecting all of the following metals, EXCEPT... O Silver Aluminum O Copper Lead O Iron Question 47 2...
Using the table below:
19. Three combinations of metals are listed below, which
combination would produce the largest voltage if they were used to
construct an electrochemical cell?
Copper (Cu) with zinc (Zn)
Lead (Pb) with zinc (Zn)
Lead (Pb) with cadmium (Cd)
Liu lur the reaction between Zn and Cu2+ ions is 1.1030 V, we can use the known value for the half-cell potential for zinc to determine the half-cell potential for copper: Zn(s) → Zn2+(aq) + 2e +...
Using the information in the table:
Which combination of metals, if used to create an
electrochemical cell, would produce the largest voltage?
Liu lur the reaction between Zn and Cu2+ ions is 1.1030 V, we can use the known value for the half-cell potential for zinc to determine the half-cell potential for copper: Zn(s) → Zn2+(aq) + 2e + Cu2+(aq) + 2e → Cu(s) Zn(s) + Cu2+ (aq) → Zn2+ (aq) + Cu(s) E half-cell = 0.7628 V Eºhalf-cell =...
materials question electrochemistry
table has associated voltages
compute the voltage at 25c of an electrochemical cell
consisting of pure copper immersed in 9x10^-2M solution of Cu^2+
ions and pure nickel in a 0.35 M solution of Ni^2+ ions.
half reactions are:
Cu-> Cu^2+ + 2e- @+0.345V electrode potential
Ni-> Ni^2+ + 2e- @ -2.250V
this is all the information I was given
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