An ice cube is placed o top of an overturned spherical bowl of radius R. as...

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Answer 1

Answer #1

Here, N + mv²/R = mgcos(theta)

=> applying consevation of energy

=> 1/2 * m * v² = mgR * (1 - cos(theta))

=> putting N = 0

=> v²/R = gcos(theta)

=> 2gR * (1 - cos(theta))/R = gcos(theta)

=> 2 * (1 - cos(theta)) = cos(theta)

=> coa(theta) = 2/3

=> theta = 48.189 degree

Answer 2

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