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Problem #3 Please see below a beam. The beam is made up of three sections: Youngs modulus and cross section area is E and 2A

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E, 2A 2E, A E,2A 3L al x-3L seehion E, 2A S= FL Smo = FL Hese Aree = 24 QA E at n: 2L seehone 2E,A Sec = FL %3D A 2E fare bis

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