Question

Distributions Fiber Quantiles 100.0% maximum 99.5% 97.5% 90.0% 75.0% quartile 50.0% median 25.0% quartile 10.0% 2.5% 0.5% 0.0% minimum Summary StatisticsConfidence Intervals 36.8 Mean 35.988 Std Dev 12.788571 5.3301925 0.3003223 Upper 95% Mean 13.37947 Lower 95% Mean 12.197673 315 Parameter Estimate Lower Cl Upper Cl 1-Alpha Mean Std Dev 12.78857 12.19767 13.37947 0.950 5.330192 4.943922 5.782442 0.950 Std Err Mean 26.21 19.44 15.6 12.1 N 9.1 6.42 5.09 3.448 3.1 5 10 15 20 25 30 35
C.37 – Grams of Fiber per Day

Question C.37 is one of the review exercise questions for Unit C which is just after Chapter 6.

Use JMP to compute a 95% confidence interval (include output from JMP, data provided on Canvas): (provided picture)

Interpret interval in the context of this study:

Hypothesis test: ? = 0.05

Hypothesis statements:

Compute test statistic (show calculations). Note that the sample standard deviation = s = 5.33.

Find p-value using JMP (include output from JMP, data provided on Canvas; no credit will be given if JMP output is not provided):

Formal decision and why:

The conclusion

in the context of this study:

Answer 1

dear student, please post the question one at a time

C-35) degree of freedom = n-1=9

t distribution is symmetric

The area to the right of 2.75 is P value for the one-tailed test for degree of freedom = 9 and t = 2.75

The area to the right of 2.75 is 0.0112

C-36) degree of freedom = n-1=23

t=-1.5

P value for the one tailed test =0.0736