Question

To determine the salt formed during a neutralization reaction, combine the anion formed by the dissociation of the acid and the cation formed by the dissociation of the base in a ratio that results in a neutral, ionic compound. For example, if you have a cation with a 1+ charge and an anion with a 2- charge, you will need two cations to balance the charge. [(1+ charge on cation)(2)]+[2 - charge on anion)(1)] = (+2) + (-2) = 0 Complete the following statements regarding the number of cations and anions present in the various ionic compounds. Match the numbers to the appropriate blanks in the sentences below. Make certain each sentence is complete before submitting your answer. 1. The potassium chloride, is composed of potassium [K^+] cation(s) and chloride (Cl^-) anion(s). 2. The salt sodium carbonate is composed of sodium (Na^+) cation(s) and carbonate (CO_2^2-) anion(s). 3. The salt calcium chloride is composed of calcium (Ca^2+) cation(S) and chloride (Cl^-) anion(s). 4. The salt aluminum sulfate is composed of aluminum (Al^2+) cation(s) and sulfate (SO_4^2-) anion(s). 5. The salt copper (II) phosphate is composed of copper (Cu^2+) cation(s) and phosphate (PO_4^3-) anion(s). When balancing equations subscripts can never be changed because this reflects a change in the molecular structure for example charging CO_2 to CO results in a different molecule. To balance an equation the coefficients are charged so that the number of each type of atom on the reactant side of the equation equals the number of each type of atom on the product side of the equation. Start by balancing storm that appear is the most complex structures and in the most structures first. Balance elements that occur by themselves last if a fractional coefficient is prevent in the chemical equation then multiply all of the co using whole-number coefficients.

Answer 1

4- Na, lo ス 3 2 2 从1s 3 3 3 2