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6. Given the vectors vi = - 0 -- --(2.).-) no estaba 1. vz = 2 .03 = 1 -1 1 62-5) ,0 = 3, find the value(s) of k so that: de
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com a) Wn is in span City, VI, Ihs). So, consides W + Ja + cu = Fy 84)01:13) DEN Augmented mattix is rii -1 1 -2] Ti 2 3 Ti9 : | 6 6 2 –ฯ | k - % other, k²-420 k = 2, 2) and K-2=0 \ = 2 Thus common value of k in 2.Solh b) sf {v}, 5, 5 } be the linearly independent set, then det (T), J J})=0 LIII - co III k2-5 | 1(2K²-10-1)-1(K²-5-1)-1(1-

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