Please help me with this problem but please only help if you know how to do it 100% and please circle answers
Homework Answers
(1)
Let Q the amount of heat to be removed,
Q = m [C(0-25) - 79.8 + C'(-5 -0)]
Q = - 2100*(25 +79.8 + 0.50*5) = - 225330 cal = -942780.72 J
(2)
The electrical energy consumed is
E = |Q|/COP = 942780.72/2.40 = 392825.3 J
(3)
The heat rejected to the room is:
Q' = |Q| + E = 1335606.02 J
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Please help me with this problem but please only help if you
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THANK YOU :))
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