Question

A freezer has a coefficient of performance of 2.60. The freezer is to convert 1.86 kg of water at 29.0°C to 1.86 kg of ice at -5.0 °C in 1 hour. Part A What amount of heat must be removed from the water at 29.0°C to convert it to ice at -5.0 °C? Express your answer in joules. V AEQ za x V Yx î 1X1 X:101 101 = 3.35.109 Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Part B How much electrical energy is consumed by the freezer during this hour? Express your answer in joules. ALPA O a ? WE Submit Request Answer

Answer 1

A mass of watch m= 1186 kg Specific heat s = 4 200 J/kg Initial temperature, o = 29.0°c Heat energy removed to cool to O₂ = 0% is DQ, = MA AO= 1.86x4 2007 29.072.26x105 J Heat energy removed in freezing Warrat A = mL = 1.86x3.36*105 = 6.25 x 105 J La Latent Head of fusion of ice = 3.36x105 Flag Heat energy removed to cool ice from o to -5c AQ=ms oo=1-86*210085 = 1.95+104 J s-specific heat of ice= 2100 F/kg- is Total energy to be removed, AQ= AQ, +OQ+0.93 Aa=8071x105 5 (B ) Coefficient of performance, k= 2.60 i. W ork done by electrical energy cor, electrical energy consumed. We Do_8.714105 - K = 2060 = 3.35*105 J 0 Amount of Heat rejected to room, qwa AQ TW = 8.71*105 +3.35*105 12.06 X10 J