Question

s is first order in the reac ich reaction is fastest if the reactants are the same? All be reactant abled. -Br₂(g) → and [Br.] ed [NO] The fol reaction ] is increased 14.59. Each of the following reactions is for and second order overall. Which res initial concentrations of the reactants reactions are at 298 K. 2. C10 (8) + O2(g) → CIO(g) + O. = 3.0 X 10-cm/(molecules) b. CIO.(g) + NO(g) → NO2(g) + CIO k = 3.4 x 10 cm/(molecules) C. CIO(g) + NO(g) → CI(g) + NO.(c) k = 1.7 10 cm/(molecules) d. CIO(g) + O2(g) - CIO.(g) + 0,() k = 1.5 x 10 cm molecules) 14.60. Two reactions in which were is a single reactanth the same magnitude a constant. One is firs other is second order. a. If the initial concentrations of the reactants are both 1.0 mM, which reaction will proceed at the higher b. If the initial concentrations of the reactants are both 2.0 M, which reaction will proceed at the higher rate Experiment nd [Br.] is a single reactant have ticarly One is first order, the d O₂ are rst order in Determi reaction 14.64. The follo reaction oxygen: nitrogen + Mg) olecule by it. The Experiment 14.61. The rate constant for the decomposition of N, O, to NO. and 02, 2 N,O3(g) → 4NO2(g) + O2(g) is 3.4 x 10-5 5-1 at 298 K. What is the rate law expression for the reaction at 298 K? 14.62. Hydroperoxyl Radicals in the Atmosphere During a smog event, trace amounts of many highly reactive substances and present in the atmosphere. One of these is the hydroperoxyl Determin rate const

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Answer 1

14.621 The given reaction is - 240249) + 50,68 ) H2503(9) 420,(9) Rate of the reaction is directly proportional to the reactant concentration. Rade o [H023a. [303] or; Rate = K [HQ]? [3033 -50 Ka rate consta = 2.6810" M-'srl at 298 K (given) &= order of the reaction with respect to PHO2 ß z onder of the reaction with respect to 393 Xaß = overall rate order of the reaction. When, conc. of HO₂ is doubled, then rate is doubled. 2x Rate K. [2x40,]? [Son] uig When, conc. of 303 is doubled then rate is doubled. 2x Rate = kif Hoja (2000,78 yung Equn vig is divided by equin is, 2x Rexte 4.2% (Hoja [SoyB Ratex [Hoga Isloß or, a=24 or, 2'224 or, a=1 Equn 115 is divided by eque vou 2x Rated K [Hoge 23 [sot? Rate - K Hoja . I soggß. 2= 2 on, 2': 2 or, B=1 CSscanned with CamScanner

- Then over all rate order a atß = 1+1=2 4 for this reaction nate law is Rate = 2.6**0"! [10,] [800]' CScanned with CamScanner