Question

1. Consider the gas of electrons in gold, as in problem 3 above. (a) Begin by assuming the gas obeys classical statistics. Using the Som- merfeld model for the density of states, an analysis shows that the partition function in the MB distribution is given by (where V is the volume) m3/2v Plug this into the MB distribution and plot N(E) as a function of E. Assume a temperature T 300 K and that the piece of gold is 1 cm3 in volume. (b) Now, plot N(E) as a function of E for the Fermi-Dirac distribution, making the same assumptions about T and V as in (a). You may use the value of the Fermi energy you calculated in problem 3 (if you did not complete problem 3 look up the Fermi energy for gold). Compare your two plots. Do they have the same shape? Do they agree better at high or low energy? Do they peak at the same energy?

​Try to avoid handwriting please, thank you.

Answer 1

Given that The gas OP electrons in a gold The partition function MB distribution of Z = m^3/2 V/squareroot 2 pi^3 h^3 (k_B T)^3/2 where V is volume The gas obey�s classical states and the sommefeld model the density states The MB distribution and plot N(E) function - E Temperature T = 300 k The piece of gold is 1 cm^3 in volume The comparison between MB and FD distribution in the below graph. \r\n plot N(E) function E The F-D distribution making the same assumption of Temperature - T volume - V The Comparison between MB & FD distribution phi At the room temperature T = 300