Question

Three point charges are arranged as shown below. 0.46 m 0.23 m + -15 °C +35 °C -95 °C What are the magnitude and direction of

I have calculated the answer 4.6 N, but I am unsure if the direction is left or right.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Let In @=-15, uc 1 91=+35mc 22= -95 uc Force = K Qiro 9x109x615) x (3D),X 10-12 eg he UGIL 9 and k kQga. - 22.33 N 9x100 X (-

Add a comment
Know the answer?
Add Answer to:
I have calculated the answer 4.6 N, but I am unsure if the direction is left...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • KILVC Four electric charges are located at the vertices of a square, as shown in the...

    KILVC Four electric charges are located at the vertices of a square, as shown in the table below the "starred" charge due to the other three? . What is the electric force on Charge (C) 1.9.HC 3.3 HC 4.6.HC 5.8.uC Vertex (m) (0, 0) (0.46.m, 0) (0.46.m, 0.46.m) (0,0.46.m) 15. magnitude a. 2.127 N b. 2.305 N c. 1.367.N d. 2.539 N 1.458 N f 1.164.N direction (as rotation angle) a. 333.2 b. 331.1 с. 337.90 d. 330.6° e. 348.3...

  • For starters, calculate the magnitude and direction of the electric field due only to charge q1...

    For starters, calculate the magnitude and direction of the electric field due only to charge q1 at this point. Down Up Left Right Incompatible units. No conversion found between "N" and the required units. Tries 0/10 Previous Tries Calculate the magnitude and direction of the electric field due only to charge q2 at this point. Down Up Left Right Tries 0/10 Calculate the magnitude and direction of the electric field due only to charge q3 at this point. Down Up...

  • I try every example to help me solve it and the computer still says I am...

    I try every example to help me solve it and the computer still says I am wrong even if I am following the equations exactly. Thank You C o webassign.net web/Student/Assignment-Responses/submit?dep=2310631& GVES PRACTICE IT Use the worked example above to help you solve this problem. Charge 4, = 7.50 PC is at the origin, and charge 42 = -5.35 pc is on the r-axis, 0.300 m from the origin (see figure). (a) Find the magnitude and direction of the electric...

  • (a) Determine the electric field strength at a point 1.00 cm to the left of the...

    (a) Determine the electric field strength at a point 1.00 cm to the left of the middle charge shown in the figure below. (Enter the magnitude of the electric field only.) N/C (b) If a charge of −7.15 μC is placed at this point, what are the magnitude and direction of the force on it? N PLEASE ANSWER BOTH A AND B. THANK YOU SO MUCH IN ADVANCE!!!! i Safari File Edit View History Bookmarks Window Help 23% D Thu...

  • Four point charges are arranged in this configuration. All four are equal in magnitude but a...

    Four point charges are arranged in this configuration. All four are equal in magnitude but a and c are negative while b and d are positive. 3)  At a distance d below charge c, in which direction does the electric field point due to all the charges? right left down up the net field is zero 4)  Halfway between charges a and c, in which direction does the electric field point due to all the charges? right left down up the net...

  • I am needing help visualizing this problem. I 'think' I have the answer correct, but am...

    I am needing help visualizing this problem. I 'think' I have the answer correct, but am not sure if I truly understand the question. The question is asking for the electric field. Is this the only equation with electric field or are there others? E = F/q F = 2.00x10-5 N q = -1.75µC (which converts to -1.75x10-6C) E = 2.00x10-5 N / -1.75x10-6C = -1.14x10-11 N/C ? E = -1.14x10-11 N/C ? Question: What is the magnitude and direction...

  • Please show your work. I have been stuck on this problem for hours and have no...

    Please show your work. I have been stuck on this problem for hours and have no idea what I am doing wrong. Thank you! Eg 0.400 m 0.500 m 0.300 m ริเ 12 The resultant electric field E at P equals the vector sum E 2 where E is the field due to the positive charge gi and E2 is the field due to the negative charge q2 (a) Place a charge of-4.30 μC at point P and find the...

  • Two equal positive charges 91 = 42 = 2.0 nC are located at * = 0,...

    Two equal positive charges 91 = 42 = 2.0 nC are located at * = 0, y = 0.30 m and x = 0, y -0.30 m, respectively. What are the magnitude and direction of the total electric force that 41 and 42 exert on a third charge Q= 4.0 uC at x = 0.40 m, y = 0? Select one: O A. 0.92 N-x direction B. 0.23 N +x direction C. 0.46 N +x direction D. 0.23 N -x...

  • ​ Three point charges lie along a straight line as shown in the figure below

    Three point charges lie along a straight line as shown in the figure below, where q1 = 6.30 µC, q2 = 1.59 µC, and q3 = -2.12 µC. The separation distances are d1 = 3.00 cm and d2 = 2.00 cm. Calculate the magnitude and direction of the net electric force on each of the charges.Three charges lie along a horizontal line. Positive charge q1 is on the left. Positive charge q2 is a distance d1 to the right of...

  • In the following situation, q1 has a charge of 4e and q2 has a charge of...

    In the following situation, q1 has a charge of 4e and q2 has a charge of e. The two point charges are separated by a distance of r 2.7 m. 41 42 What is the magnitude of the electric field at q2 due to q1? 7.89x10-10 N/C What is the direction of the electric field at q2 due to q1? to the right You are correct. のPrevious Tries Your receipt no. is 159-2596. What is the magnitude of the electric...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT