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Eg 0.400 m 0.500 m 0.300 m ริเ 12 The resultant electric field E at P equals the vector sum E 2 where E is the field due to the positive charge gi and E2 is the field due to the negative charge q2(a) Place a charge of-4.30 μC at point P and find the magnitude and direction of the electric field at the location of q2 due to q1 7.30 HC and the charge at P. magnitude Your expression for E is correct, but your values for Ex and/or Ey were incorrect. Check your trig. N/C direction Refer back to your diagram of the system. Use the directions of the field arrows help you to estimate the direction and relative size of the total field.0 (b) Find the magnitude and direction of the force on q2 What is the relationship between the magnitude of the electric force and the magnitude magnitude of the electric field? Refer back to your diagram of the situation. Use the directions of the field arrows help you to estimate the direction and relative size of the total field. N

Please show your work. I have been stuck on this problem for hours and have no idea what I am doing wrong. Thank you!

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Please find attached the solution, please comment if you are able to find the right solution.

-4.3P vi 구,3 5 : 7.3メ10 Elechic pld dus to chargc at pad. : 1.5 5x10s s..3 in y dirh 5 6.3 7 6-27 force on 4

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