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Eg 0.400 m 0.500 m 0.300 m ริเ 12 The resultant electric field E at P equals the vector sum E 1 +E, where is the field due to the positive charge q1 and E2 is the field due to the negative charge q2(a) Place a charge of-4.30 μC at point P and find the magnitude and direction of the electric field at the location of q2 due to q1: 7.30 μC and the charge at P. N/C direction (b) Find the magnitude and direction of the force on q2. magnitude direction

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