Question

2. Two point charges Q1 40 μcoul and Q2 -120 μcoul are fixed on the xy plane as shown in the figure i! at right. 8m, a. What is the electric field at b. What is the electric field at c. What is the resultant electric ,--4m point P due to Q1? point P due to Q2 field (in unit vector form) at 2. -bm-→i point P electric field at point P? what force (in unit vector form) does it experience? d. What is the magnitude and direction of the resultant e. If a point charge (q + 1800 μcoul) is placed at point P then

f. Referring to part e, what is the magnitude and direction of the force exerted on q?

g. If q= - 1800 μcoul, how does the answer in part f change?

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Answer #1

LU に 40,AC of k-4m The electric Held at point P- u) Due toQ -4.425 X103 E, 4495 N/C 2:93X10 x10 o 2. 13485 Nc4 です = 53.13 The Net elcctic fie +L4435 Sin.43 13485 Sih 53.3 10 101.59d -6767-71 J mag niんde E 12.159.11 Nefield is ΘΙ (Clockwise) ,02 2. O 3Co -33.82 - 320 .9- 32-18 00× to Fosce on at ont P. Di-ectior is Same of E 日2-311 . I 8 ° ( Anti clockwise from ta axisF 21.89 Neuutoh F= 21.99 Newton 130 .. θ 146-18 ( Ahticlockube

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