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Place a charge of -9.40 µC at point P and find the magnitude and direction of...

Place a charge of -9.40 µC at point P and find the magnitude and direction of the electric field at the location of q2 due to q1 = 6.95 µC and the charge at P.

Magnitude N/C

Direction

(b) Find the magnitude and direction of the force on q2.

Magnitude    n/C

Direction

Eg 0.400 m 0.500 m 0.300 m 42 The resultant electric field E at P equals the vector sum E, E where E, is the field due to the positive charge gi and E2 is the field due to the negative charge q

Eg 0.400 m 0.500 m 0.300 m 42 The resultant electric field E at P equals the vector sum E, E where E, is the field due to the positive charge gi and E2 is the field due to the negative charge q
0 0
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Answer #1

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