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Using the following returns, calculate the arithmetic average returns, the variances, and the standard deviations for X and Y

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Answer #1
Solution:
1. Average return
a. 11.20% For X
b. 13.80% For Y
2 Variance
a. 307.70    %^2 or    0.03077      in decimal   For X
b. 1033.20 %^2   or   0.1033.20    in decimal For Y
3. Standard deviation
a. 17.54% For X
b. 32.14% For Y
Working Notes:
For X
a b = a - 11.2% b^2
Year Annual total return (%) R (R-r) (R-r)^2
1 10 -1.20 1.440
2 28 16.80 282.240
3 17 5.80 33.640
4 -18 -29.20 852.640
5 19 7.80 60.840
Sum of annual return 56.00 Sum of (R-r)^2 1230.80
Mean (r) = sum of returns / no of returns
Mean (r) = 56%/5
Mean (r) =11.20%
Where n = no of return considered = 5
Variance = Sum of (R-r)^2 /(n-1)
Variance = 1230.80 %^2 /(5-1)
Variance = 1230.80 %^2 /4
Variance = 307.70 %^2
OR
Variance = 0.03077
standard deviation (s.d.) = Square root of (Sum of (R-r)^2 /(n-1))
standard deviation (s.d.) = Square root of (1230.80 %^2 /(5-1))
standard deviation (s.d.) = Square root of (1230.80 %^2 /4)
standard deviation (s.d.) = Square root of (307.70 %^2)
standard deviation (s.d.) = (307.70 %^2)^(1/2)
standard deviation (s.d.) = 17.5413796%
standard deviation (s.d.) = 17.54%
For Y
a b = a - 13.80% b^2
Year Annual total return (%) R (R-r) (R-r)^2
1 19 5.20 27.040
2 40 26.20 686.440
3 -12 -25.80 665.640
4 -26 -39.80 1584.040
5 48 34.20 1169.640
Sum of annual return 69.00 Sum of (R-r)^2 4132.80
Mean (r) = sum of returns / no of returns
Mean (r) = 69%/5
Mean (r) =13.80%
Where n = no of return considered = 5
Variance = Sum of (R-r)^2 /(n-1)
Variance = 4132.80 %^2 /(5-1)
Variance = 4132.80 %^2 /4
Variance = 1033.20 %^2
OR
Variance = 0.10332
standard deviation (s.d.) = Square root of (Sum of (R-r)^2 /(n-1))
standard deviation (s.d.) = Square root of (4132.80 %^2 /(5-1))
standard deviation (s.d.) = Square root of (4132.80 %^2 /4)
standard deviation (s.d.) = Square root of (1033.20 %^2)
standard deviation (s.d.) = (1033.20 %^2)^(1/2)
standard deviation (s.d.) = 32.143428%
standard deviation (s.d.) = 32.14%
Please feel free to ask if anything about above solution in comment section of the question.
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