QUESTION # 1
A random sample of 5,280 permanent dwellings on an entire reservation showed that 1,634 were traditional hogans.
(a)Let p be the proportion of all permanent dwellings on the entire reservation that are traditional hogans. Find a point estimate for p. (Round your answer to four decimal places.)
(b)Find a 99% confidence interval for p. (Round your answer to three decimal places.)
lower limit
upper limit
QUESTION #2
A random sample of 5,100 permanent dwellings on an entire reservation showed that 1,690 were traditional hogans.
(a)Let p be the proportion of all permanent dwellings on the entire reservation that are traditional hogans. Find point estimates for p and q. (Round your answer to four decimal places.)
p̂=
q̂=
(b)Find a 99% confidence interval for p.
Find the maximal margin of error, E. (Round your answer to three decimal places.)
E =
Report the bounds from the 95% confidence interval for p. (Round your answers to three decimal places.)
lower limit
upper limit
Solution :
Given that,
1) n = 5280
x = 1634
a) Point estimate = sample proportion = = x / n = 1634 / 5280 = 0.3095
1 - = 1 - 0.3095 = 0.6905
b) At 99% confidence level
= 1 - 99%
=1 - 0.99 =0.01
/2
= 0.005
Z/2
= Z0.005 = 2.576
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 2.576 (((0.3095 * 0.6905) / 5280)
= 0.016
A 99% confidence interval for population proportion p is ,
± E
= 0.3095 ± 0.016
= ( 0.294, 0.326 )
lower limit = 0.294
upper limit = 0.326
2) Given that,
n = 5100
x = 1690
a) Point estimate = sample proportion = = x / n = 1690 / 5100 = 0.3314
q̂= 1 - = 1 - 0.3314 = 0.6686
b) At 99% confidence level
= 1 - 99%
=1 - 0.99 =0.01
/2
= 0.005
Z/2
= Z0.005 = 2.576
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 2.576 (((0.3314 * 0.6686) / 5100)
= 0.017
A 99% confidence interval for population proportion p is ,
± E
= 0.3314 ± 0.017
= ( 0.314, 0.348 )
lower limit = 0.314
upper limit = 0.348
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