The electric field strength is 2.20×104 N/C inside a parallel-plate capacitor with a 1.20 mm spacing. An electron is released from rest at the negative plate.
F = qE = 1.6*(10^-19) * 2.20×10^4 = 3.52*(10^-15) N
F = ma
or, a = F/m = [3.52 *(10^-15)] / [9.1 × (10^-31)] = 3.868 * (10^15)
m/s^2
v^2= u^2 + 2ax = 0 + 2*[3.868 * (10^15)]*[1.2*(10^-3)] = 9.28*
(10^12)
or, v = sqrt (9.28* (10^12) ) = 3.046 * (10^6) m/s
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