Question

please answer all pre-lab questions 1 through 5. THANK YOU!!!

this is the manual to give you some background.

Lab Manual Lab 10: String Waves & Resonance Before the lab, read the theory in Sections 1-3 and answer questions on Pre-lab Submit your Pre-lab at the beginning of the lab. During the lab, read Section 4 and follow the procedure to do the experiment. You will record data sets, perform analyses, answer questions, and have Check Boxes checked on Report Sheets, Submit your Report Sheets before you leave the lab. 1. Introduction This lab explores oscillatory motion of a string in the form of transverse waves. We will gen- erate standing waves on a string as a superposition of two transverse waves. We will study how the waves' physical properties, such as wavelength, frequency, and propagating speed, depend on the string's mass and tension. In addition, we will externally drive a spring oscillator and try to induce and observe the resonance phenomenon. 2. Key Concepts .Transverse waves . Standing waves and nodes . Simple harmonic oscillation Wave speed . Frequency and wavelength 3. Theory 3.1 Transverse waves on a string As shown in Figure 1, when one shakes the of the rope end of a level string up and down, the dis- turbance will propagate along the string., Figure 1: Generating transverse forming transverse waves. The term "trans- verse" means that the direction of wave is perpendicular to the direction of disturbance. The shape of wave can be described by the disturbance (say y coordinate) at a given position on the string (x coordinate) and at an instant t, as y(x, t). If the shaking end undergoes a simple har- monic motion, the wave becomes sinusoidal as Direction of wave waves on a string yx,)-Asinx2ft

the pre-lab questions..

the pre-lab sheet.

Answer 1

Y + (x_1 t) = A sin (2 pi x/lambda - 2 pi f t) y - (x, t) = A sin (2 pi x/lambda + 2 pi f t) Y_sw = y + (x, t) + y - (x, t) = A sin (2 pi x/lambda - 2 pi f t) + A sin (2 pi x/lambda + 2 pi f t) + A {Sin (2 pi x/lambda) cos (2 pi f t) + cos (2 pi x/lambda) sin (2 pi f t)] Y_SW = 2 A Sin (2 pi x/lambda) cos (2 pi f t) v = squareroot T/mu therefore V^2 = T/mu therefore mu = T/V^2 therefore Inverse of slope will give mu y-intercept = 0, which implied V = 0 iff T = 0 \r\n f_1 = v/2 L f_2 = 2 f_1 f_3 = 3 f_1 f_n = n f_1 therefore f_2/f_1 = 2/1 = 2 f_3/f_2 = 3/2 = 1.5 f_4/f_3 = 4/3 = 1.33 f_5/f_4 =