Question

This scenario is for questions 1-2 A simple harmonic oscillator at the position x-Ogenerates a wave on a string. The oscillator moves up and down at a frequency of 40.0 Hz and with an amplitude of 3.00 cm. At time t = 0, the oscillator is passing through the origin and moving down. The string has a linear mass density of 50,0 g/m and is stretched with a tension of 5.00 N. a) Find the angular frequency of the oscillator. b) If we express the oscillator's motion as y(t) = A cos(wt +f), what is the phase angle f? c) At what time t will the oscillator be at its maximum positive displacement of 3.00 cm? d) Find the speed of the wave down the string. e) Find the wavelength of the wave on the string. f) Draw a snapshot of the wave at t = 2.5 s. Please put numbers on both axes. Upload Choose a File 29 W

can you help with a-f please

Answer 1

to M=50 g/m T=5N a) W = 20 f = 0oT radis = 2510327 rad/s. b) f = 1 as it is moving towards are side at origin. o t= t= 3T 31 = 34 21 a 3 TI 4 3TI y 2 W - 3 2x80 Ti 160 t=0 -0.01875 sec. E = Tlu E=512 314 a) V= T 5 a lomis 50x103 e) de v 10 ५० = 0.25m NE = 25m in 2.5 see wave will move by wich is equal to lood. > Va comisi Y=3 km x 0.25m