Question

This scenario is for questions 1-2. A simple harmonic oscillator at the position x = 0 generates a wave on a string. The oscillator moves up and down at a frequency of 40.0 Hz and with an amplitude of 3.00 cm. At time t = 0, the oscillator is passing through the origin and moving down. The string has a linear mass density of 50.0 g/m and is stretched with a tension of 5.00 N. a) Find the angular frequency of the oscillator. b) If we express the oscillator's motion as y(t) = A cos(wt +f), what is the phase angle f? c) At what time t will the oscillator be at its maximum positive displacement of 3.00 cm? d) Find the speed of the wave down the string. e) Find the wavelength of the wave on the string. f) Draw a snapshot of the wave at t = 2.5 s. Please put numbers on both axes.

Answer 1

Solution in the uploaded images

a solution ve Yo H₂ A= 3cm At t=0, ay(o)=0 u= sogn, Tension = 5N f 12 T (a) (b) Angular frequency, w = 21 W=2x1TX 40 w = 251.33 rad's From equation: y (t)- A Cas(wt ++) given, at tao, y(t)=0 y(a) = A Cas (o+f) O = A Los(f) phese angle, L f = 0 The equation g(t) = A Cas(wt) For masimum displacement y(t) = 3 QaBee56334) SHM is, J 3. Casal &1886 ting to time, t= I 4. to - T = Time period - + uta stime, It 6.25msee 4x40

(d) Speed of were in a string is given as, E purfing waters W= 50x103 U=10m/s Tu e wave length, A=4 0.25m d 10 yo For remaining que l'ons, upload Hem separately!