Example 4: Suppose that A, B, C, and D represent four people, who have tickets for...

Question

Question

Answer 1

Answer #1

We need to make A and B sit together but they can be arranged in themselves in 2 ways i.e. AB or BA. Then we will have 2 people and 1 group. Hence,

Number of different ways = 2! * 3! = 2* (3*2*1) = 2*6 = 12

Answer 2

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