Six people A, B, C, D, E, and F, have decided to go to the movies....
Six people A, B, C, D, E, and F, have decided to go to the movies. The night before, E and F had an argument about statistics and cannot sit next to one another. How many different ways can A, B, C, D, E, and F sit in a row such that E and F DO NOT sit next to each other?”
Homework Answers
Number of ways that six people sit in a row = 6! = 720
(Consider E and F one entiity & 2! Ways for E and F sitting )
Number of ways E and F sit to gather =2! * 5!
Number of ways can A,B,C,D,E and F sit in a row such that E and F do not sit to each other
= 6! - (2! * 5!)
= 720 - 240
= 480
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