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In the circuit shown in the figure, the battery is
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Answer #1

in LR circuit, at t=0, inductor acts as an open circuit

L/R = 11.1/32.8 = 0.338 ms

i = io (1 - exp(-Rt/L))

a) io = 14.3/(11.9 + 20.9) = 0.436A

b) not possible

c) at steady state condition, it acts as a short circuit

i = 14.3/ 20.9 = 0.684A

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