A uniform magnetic field equal to 1.48 T k is in the +z direction. Find the force exerted by the field on the protein if the velocity of the protein is (a) 2.7 km/s i (b) 3.7 km/s j (c) 6.8 km/s k and (d) 4.0 km/s i + 3.0 km/s j.
a)
q = 1.602 * 10^-19 C
Fb = q ( v * B)
Fb = 1.602 * 10^-19 * 3.996 * 10^3
Fb = 6.40 * 10^-16 N
b)
Fb = 1.602 * 10^-19 *5.476 *10^3
Fb = 8.772 * 10^-16 N
c)
Fb = 0 N
d)
magnitude of ( v *B) = sqrt(-4.44^2 + 5.92^2) = 3.91
then
Fb = 1.602 * 10^-19 * 3.915 * 10^3
Fb = 6.27 * 10^-16 N
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