We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
An electron with velocity v = (12 m/s) i moves through a magnetic field B =...
An electron with velocity (12 m/s) i moves through a magnetic field B - (4.0). J. and k denote unit vectors pointing along the x, y, and axes, respectively. Find the magnitude of the force on the electron 4.7.7 * 10-18 6.3.3 * 10-19 C. 48 N d. 6.0 N
QUESTION 2 An electron with velocity v - (12 m/s) i moves through a magnetic field (4.0T), and denote unit vectors pointing along the x, , and axes, respectively.) Find the direction of the force on the electron b) c-k d.-1
answer both QUESTION 1 An electron with velocity - (12 m/s) i moves through a magnetic field B - (4.0T) k. (i), and k denote unit vectors pointing along the x, y, and axes, respectively.) Find the magnitude of the force on the electron 08.77* 10-18N b.3.3 * 10-19 C. 48 N d. 6.0 N QUESTION 2 An electron with velocity - (12 m/s) i moves through a magnetic field B - (4.0T) k. (.), and k denote unit vectors...
An electron that has velocity v=(3x10^5 m/s) and moves along positive x direction through the uniform magnetic field B=(0.8T) which is along the positive z direction. (a) Find the force on the electron (magnitude and direction). (e=1.6x10^-31 kg) (b) Calculate the radius of the electron's path in the magnetic field.
A proton moves with a velocity of v-(3i-j+k) m/s in a region in which the magnetic field is B - +2j-i)T. What is the magnitude of the magnetic force this particle experiences? A proton moves with a velocity of v-(3i-j+k) m/s in a region in which the magnetic field is B - +2j-i)T. What is the magnitude of the magnetic force this particle experiences?
An electron moves through a uniform magnetic field given by B = Bxi+(3.74Bx)j. At a particular instant, the electron has velocity V =(2.88i+4.37j)m/s and the magnetic force acting on it is (2.74x10^-19)k N. Find Bx An electron moves through a uniform magnetic field given by B 3.74 B . At a articular instant, the electron has velocit y 2.88 , -37 m/s and the magnetic orce acting on t is 7 ·r Linda Number Units
An electron moves with velocity v ⃗ =(6.8i−5.3j)× 10 4 m/s in a magnetic field B ⃗ =(−0.64i+0.57j)T . Part A Determine the x-component of the force on the electron. Express your answer using two significant figures. Fx = N Part B Determine the y-component of the force on the electron. Express your answer using two significant figures. Fy = N Part C Determine the z-component of the force on the electron. Express your answer using two significant figures....
An electron moves through a uniform magnetic field given by B -a, i +(2.05 a.) j . At a particular instant, the electron has velocity V-(1.67 +3.79 m/s and the magnetic force acting 67 x 101%) N. Pind B Units
An electron moves through a region with a uniform magnetic field of unknown magnitude directed in the +y direction At the instant that the electron is moving in the +z direction with a velocity of 2.86e6 m/s, it experiences a magnetic force of 1.24 pN in the +x direction. Calculate the magnitude of the magnetic field
An electron travels through the uniform magnetic field of field strength B = (2.5 i + 3.5 j ) mT and electric field of field strength 4.00 I V/M . If the electron is moving with the velocity v= (1500 j + 2000 k)m/s. Calculate the net force acting on the electron in terms of unit vector notation.