An electron that has velocity v=(3x10^5 m/s) and moves along positive x direction through the uniform...
An electron that has velocity v=(3x10^5 m/s) and moves along positive x direction through the uniform magnetic field B=(0.8T) which is along the positive z direction.
(a) Find the force on the electron (magnitude and direction). (e=1.6x10^-31 kg)
(b) Calculate the radius of the electron's path in the magnetic
field.
Homework Answers
a. F = qvB
F = 1.6*10^-19 * 3*10^5 * 0.8 = 3.84 *10^-14 N
b. r= mv/qB
r = 9.11*10^-31* 3*10^5/1.6*10^-19 * 0.8
r = 2.13 um
F= qvB
F=1.6 * 10 ^ -19 *3 * 10 ^ 5*0.8=3.84 * 10 ^-14 N
F= m*v ^2 /r
r= m*v ^2/F
here mass of the electron is 9.1 * 10 ^31 Kg
r=81.9 *10 ^10/(3.84 * 10 ^-14)=21.32 *10^4 m
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