Homework Answers
Heat change of water(qw) = - Heat change of iron(qi)
qw = m × ∆T × C
m = mass of water , 200g
∆T = temperature change of water, 20.4℃ - 18.0℃ = 2.4℃
C = heat capacity of the water, 4.184J/g℃
qw = 200g × 2.4℃ × 4.184J/g℃ = 2008.3J
qi = m × ∆T × C
m = mass of iron , 58.4g
∆T = Temperature change of the iron , 20.4℃ - X , X is initial temperature of iron
C = heat capacity of iron, 0.449J/g℃
qi = - (58.4g × (20.4℃ - X) × 0.449J/g℃ ) = X26.222J/℃ - 534.93J
equating qw and qi
2008.3J = X26.222J/℃ - 534.93J
X26.222J/℃ = 2543.2J
X = 96.99℃
Therefore
Initial temperature of iron = 96.99℃
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