Question

In a sales effectiveness seminar, a group of sales representatives tried two approaches to selling a...

In a sales effectiveness seminar, a group of sales representatives tried two approaches to selling a customer a new automobile: the aggressive approach and the passive approach. For 1160 customers, the following record was kept:

Sale No Sale    Row Total
Aggressive 261 319 580
Passive 486 94 580
Column Total 747 413 1160

Suppose a customer is selected at random from the 1160 participating customers. Let us use the following notation for events: A = aggressive approach, Pa = passive approach, S = sale, N = no sale. So, P(A) is the probability that an aggressive approach was used, and so on.

(a) Compute P(S), P(S | A), and P(S | Pa). (Enter your answers as fractions.)

P(S) =

P(S | A) =

P(S | Pa) =

(b) Are the events S = sale and Pa = passive approach independent? Explain.

No. P(S) ≠ P(S | Pa).

Yes. The two events can occur together.    

Yes. P(S) = P(S | Pa).

No. The two events cannot occur together.

(c) Compute P(A and S) and P(Pa and S). (Enter your answers as fractions.)

P(A and S) =

P(Pa and S) =

(d) Compute P(N) and P(N | A). (Enter your answers as fractions.)

P(N) =

P(N | A) =

(e) Are the events N = no sale and A aggressive approach independent? Explain.

Yes. The two events can occur together.

Yes. P(N) = P(N | A).    

No. The two events cannot occur together.

No. P(N) ≠ P(N | A).

(f) Compute P(A or S). (Enter your answer as a fraction.)

P(A or S) =

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Answer #1

1160 0.645

PS/A) = 201-0.45 550 0.45

4860.838 P(S/Pa)0.838

b)

No. P(S) ≠ P(S | Pa).

c)

P(A and S) 261 1160 0.225

PlPa and S) = 1100 = 0.419

d)

413 1160 0.356 P(N)

P(N/A) = 580 = 0.55

e)

No. P(N) ≠ P(N | A).

f)

580 747261 1160 1160 1160 P(A or S) P(A) P(S) - P(A and S) 1066 1160 -0.919

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