Homework Answers
Weight of the small boy F1 = m1g = 40 * 9.81 = 392.4 N
Torque created by his force = T1 = F1 r1 = 392.4* 5 = 1962 N m
Weight of man = 80* 9.81 = 784.8 N
Torque T2 = f2 r2 = 784.4 * 3 = 2354.4 Nm
Let the mass of the board be m3
Its weight = m3 * 9.81
Torque T3 = m3* 9.81 *1
So now from balancing condition from the seesaw
Sum of torques of CW moments = sum of CCW moments
i.e M2-M3-M1 =0
2354.4– m3* 9.81 -1962
m3 = 40 kg
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