Question

I need help plotting the mass of precipitate versus moles of Pb(NO3)2 .

Reaction Equation: Pb(NO3)2 + 2KBr → PbBr2 + 2KNO3

Volume (mL) Solution Mixture 0.50 M Pb(NO3)2 0.50 M KBT 2.00 18.00 4.00 16.00 6.00 14.00 8.00 12.00 10.00 10.00 12.00 8.00 14

Data Collection | Experimental Data Assignment Number Volume Pb(NO3)2 16m Moles Pb(NO3)2 Volume KBr 114 mL Moles KBT Mass of

Moles of Pb(NO3)2 (mol) Mass of Precipitate (g) 0.001 0.002 0.003 0.634 0.004 0.005 0.006 0.007 0.008 0.009

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According to for plotting your arestim I only give you the data and the pream of calculation of data. 1. Pb(NO3)2 + 2 kBr PL

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