Question

QUESTION 29 Continuing with Scenario C (from Question #24): a physical therapist conducts a study examining the effect of implementing a group exercise program at an assisted living facility for elderly adults. One group of residents is selected to participate in the program, and a second group serves as a control. After 6 weeks, the researcher records a combined score measuring balance and strength for each individual. Control group: n= 11, M=13, SS= 124.5. Exercise group: n=10, M=17.2, SS=180. Construct a 95% confidence interval for the estimated difference in sample means. C 0.41 to 6.39 C 0.54 to 7.86 C 0.93 to 5.87 C 4.67 to 7.63 QUESTION 30 A researcher examines the influence of marital counseling on individuals' romantic relationship satisfaction. One group of 20 married individuals participates in marriage counseling, while a second group of 20 married individuals receives no counseling. After 2 months, each participant reports on their relationship satisfaction. For the participants receiving counseling, their mean satisfaction was 4.5. The mean satisfaction for participants who received no counseling was 6.8. The pooled variance was 28. What is the Cohen's d for this example? Be sure to round your final answer to 2 decimal places.

Answer 1

Sol 99: Given that Control Exercise group group Sample Size Sample mean 24=13 72 = 17.2 Sample Sum of Squares SS = 124.5 SS = 180 Pooled variance S 4 + SS2 - 24.5 +180 Nat-2 11+10-2 s 304,5 = 16.026 19 95% confidence interval for the estimated difference in sample means is ( 74 - 753) = +0.05, Ditb-2 VSC + box) = (-1) +0.05, 19 Vs Chattu) = (3-14.2) +(2109) 16.026(++ to) = -4.2 + 2.09 16.626) (6.09914 ol) = -4.2+(2.09 3.05952 - (-4-2-3.656, -4.2+3656) = (-7.656, -0.544) -7.856 M-P 2-0.544 (or) 0.54 < H2-MI < 7-856 - 997. Confidence interval for the estimated difference M-t is (0.54, 7-86). Note: tf confidence level - 99% -0.99 ter level of Significance = 1-0.99 = 0.0L. 2. Critical value of t for at 0.01 significance lever +N2-2 = 19 degrees of freedom * + 2.09 Charles

sol 30 Given that Sample bize of married individuals = 20 Second lample of married individuals 2 = 30 The mean Satisfaction for participating indiuid who receiving counseling = 4.5: The mean Satisfaction for participants who received no Counseling is = 6.8. the pooled variance Ś=28 Standard deviation SD = 128 = 5.292. Cohen's a = 7 7 So pooled = 6.8-4.5 5.292 2.3 5.292 Cohen's d= 0.435