A 0.045 kg aluminum bullet traveling at 471 m/s strikes an armor plate and comes to a stop. If all its energy is converted to heat that is absorbed by the bullet, what is the bullet's temperature change in degrees Celsius?
Q absorbed = KE
Q = m*C*dT = 0.5*m*v^2
dT = (0.5*v^2)/(C)
dT = (0.5*471*471)/870 = 127.49 oC
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