A 41 g bullet moving a horizontal velocity of 380 m/s comes to a stop 14...
A 41 g bullet moving a horizontal velocity of 380 m/s comes to a stop 14 cm within a solid wall. (a) What is the change in the bullet's mechanical energy? (b) What is the magnitude of the average force from the wall stopping it?
Homework Answers
a)
here
delta E = delta K = - 0.5 * m * v0^2
delta E =- 0.5 * 0.041 * 380^2
delta E = 2.96 * 10^3 J
b)
then force = delta E / d
F = 2.96 * 10^3 / 0.14
F = 2.1 * 10^4 N
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