we want to find the speed of the diver on hitting the water, so
we use
acceleration = change in velocity / time
then , we use F = m*a to find force
if his initial vertical velocity was zero, then his speed hitting
the water is given by:
vf^2 = v0^2 + 2*a*d
vf = final velocity
v0 = initial velocity = 0
a = 9.8 m/s^2
d=10 m
vf = sqrt [2*9.8 *10] =14m/s
now, we apply this equaiton again to get his acceleration caused by
the water:
acceleration = change in velocity / time
a = (0 - 14) /1.80 = 7.77 m/s^2
therefore, F = m*a = 63 * (-7.77) =-490 N
the minus signs indicate the force acts opposite to the direction
of motion
m*g = 63*9.81
average upward force = 490 + 63*9.81
average upward force = 1107.4 N
A high diver of mass 63.0 kg Jumps off a board 10.0 m above the water....
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