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Part A A student with mass 59 kg jumps off a high diving board. Using 6.0x1024 kg for the mass of the earth, what is the acce

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Answer #1

Part A

m is mass of diver, M is mass of earth.

By Newton's third law , force that diver and earth exert on each other will be same in magnitude.

Force exerted by diver on earth F_d=mg

Force exerted by earth on diver F_e=Ma

Hence mg = Ma ( a is the acceleration of the earth)

9.8 mg 59 M 6.0 1024 -9.6 10-23 m/s2

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Answer #1

Part A

m is mass of diver, M is mass of earth.

By Newton's third law , force that diver and earth exert on each other will be same in magnitude.

Force exerted by diver on earth F_d=mg

Force exerted by earth on diver F_e=Ma

Hence mg = Ma ( a is the acceleration of the earth)

9.8 mg 59 M 6.0 1024 -9.6 10-23 m/s2

Add a comment
Answer #1

Part A

m is mass of diver, M is mass of earth.

By Newton's third law , force that diver and earth exert on each other will be same in magnitude.

Force exerted by diver on earth F_d=mg

Force exerted by earth on diver F_e=Ma

Hence mg = Ma ( a is the acceleration of the earth)

9.8 mg 59 M 6.0 1024 -9.6 10-23 m/s2

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